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2x^2-67x+270=0
a = 2; b = -67; c = +270;
Δ = b2-4ac
Δ = -672-4·2·270
Δ = 2329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-\sqrt{2329}}{2*2}=\frac{67-\sqrt{2329}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+\sqrt{2329}}{2*2}=\frac{67+\sqrt{2329}}{4} $
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